import Foundation
let pattern = #"(\d+)\s+(\d{1,3}\.\d{1,3}\.\d{1,3}\.\d{1,3}:\d+)\s+(\d+)\s+([A-z\d]+)(\(OK\))?\s+((\w+[A-z]\w+\s+)+)"#
let regex = try! NSRegularExpression(pattern: pattern)
let testString = #"""
--------------------------------------------------
0 127.0.0.1:1234 16 739casd1b747171ee9038fdbeb5440f(OK) Hans Dieter
1 127.0.0.1:1234 16 c196c8077727asd7d2bc691e109904dc(OK) House P
2 127.0.0.1:1234 15 9647c2fd98asdb7c7278e820bef701c(OK) EisFrau
3 127.0.0.1:1234 16 ed018ads96a17d55c62d4b6814(OK) [S.L]EisMann
4 127.0.0.1:1234 0 1f7b7fasd0bc3ce1c300a451b0d039(OK) 0MasterCore0
5 127.0.0.1:1234 78 dbf18b744dasd326e3585f4b11d4f40(OK) Abdul (6 users in total)"
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression