re = /\b(20[0-9][0-9])\b/
str = '1920
1930
2011
2
22
222
2323
23323
2011
2009
2012
2001
2020
2022
2040
'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html